You asked: How do you find the frequency of homozygous dominant individuals?

How do you calculate homozygous allele frequency?

1 = p2 + 2pq + q2

P and q each represent the allele frequency of different alleles. The term p2 represents the frequency of the homozygous dominant genotype. The other term, q2, represents the frequency of the homozygous recessive genotype.

How do you calculate gene frequency?

An allele frequency is calculated by dividing the number of times the allele of interest is observed in a population by the total number of copies of all the alleles at that particular genetic locus in the population. Allele frequencies can be represented as a decimal, a percentage, or a fraction.

What is homozygous frequency?

In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.

How do you find the frequency of a homozygous recessive genotype?

Calculate the percentage of individuals homozygous for the dominant allele. We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09. Thus, p = 1 – q ∴ p = 1 – 0.30 = 0.70 ∴The homozygote dominants are represented by p2 = (0.70)2 = 0.49 or 49% Page 2 4.

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What is the homozygous dominant genotype?

An organism with two dominant alleles for a trait is said to have a homozygous dominant genotype. Using the eye color example, this genotype is written BB. An organism with one dominant allele and one recessive allele is said to have a heterozygous genotype.

What do PQ p2 2pq and q2 represent?

p2 +2pq + q2 = 1 Where p2 represents the frequency of the homozygous dominant genotype, q2 represents the frequency of the recessive genotype and 2pq is the frequency of the heterozygous genotype.

How do you find the frequency of a dominant allele?

Answer: The frequency of the dominant (normal) allele in the population (p) is simply 1 – 0.02 = 0.98 (or 98%). The percentage of heterozygous individuals (carriers) in the population. Answer: Since 2pq equals the frequency of heterozygotes or carriers, then the equation will be as follows: 2pq = (2)(.