How many types of gametes will be produced by the individual with genotype AaBbCcDdEe?

How many types of gametes are produced by the individual with genotype AaBbCcDd and AaBbCcDd?

Hints For Biology 101 Exam #4

No. of homologous chromosome pairs (heterozygous genes) No. of different gametes from each parent
1 (Aa X Aa) 2 (21)
2 (AaBb X AaBb) 4 (22)
3 (AaBbCc X AaBbCc) 8 (23)
4 (AaBbCcDd X AaBbCcDd) 16 (24)

What gametes can be formed by an individual with the genotype AaBbCc?

The plant having genotype AABbCC is heterozygous for only one character B. Number of “gametes = 2n”, where n is the heterozygosity.” Since n = 1 so 2 gametes will be formed. Those are ABC and AbC. So the two types of gametes will be ABC and AbC.

How many gametes are produced by AaBbCc?

Complete answer: AABbcc will produce 2 types of gametes which are as follows- ABc, Abc. The number of gametes formed is set by the number of heterozygous alleles present within the given genotype.

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What are the types of gametes that can be produced by an individual with the genotype?

An individual with the genotype Aa can make two types of gametes: A and a. Since this is a random process, the individual will, on average, make equal numbers of each gamete. (Frequency of 1/2 for each gamete). A second individual with genotype Aa can make two types of gametes: A and a.

How many different types of gametes with an individual of genotype AaBbCCddEEFF make assuming that the genes all assort independently?

The number of different possible gametes produced by the diploid genotype (AaBbCcDdEe) is 2 x 2 x 2 x 2 x 2 = 32 (2 for each pair of heterozygous genes). 15.

How many different kinds of gametes may be produced by an organism with the genotype RrYy?

Given genotype is RrYy. As RrYy is a dihybrid. A total of 4 types of gametes RY, Ry, rY, ry are formed.

How many types of gametes would be produced if the genotype of a parent is AaBB A 1 B 2 C 3 D 4?

If the genotype of a parent is AaBB then 2 types of gametes will be produced.

How many types of gametes are found in F1 progeny of cross between AABbCc and AABbCc?

Therefore, types of gametes possible is 23=8.