How many mitotic divisions are required to produce 256 cells in a root tip?

How many mitotic divisions in a root tip will form 256 cells?

(2)^n =256 (2)^8(2 raise to 8)=256 So number of mitotic division =8 after mitosis 2 daughter cells are formed.

How many mitotic divisions occur in a cell of root tip to form 256 cells a 128 B 8 C 10 D 255?

1→22→43→84→165→5 ↓5 326→647→128↓2256 It can be done with a simple formula (2)n, where n is the number of mitotic, division (2)n=256 (2)8=256(2×2×2×2×2×2×2×2=256) So, 8 mitotic division.

How many meiotic divisions are required to produce 256 cells in a root tip?

It takes 8 mitotic division to produce 256 cells in a root tip cell. Explanation: Cell division is of two types. They are mitosis and meiosis.

How many mitotic generations are required to produce 256 cells?

Complete solution:

So we can conclude that eight mitotic divisions are required to produce $256$ daughters/somatic cells.

How many mitotic divisions occur in a cell of root tip to form 128 cells?

Complete answer:

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The cell will have to divide 7 times mitotically, to form 128 cells. The number of times a cell will have to divide mitotically is calculated by the formula 2n, where n is the number of times the cell is dividing.

How many mitotic divisions must occur in a cell to form 1024 cells A 20 B 10 C 40 D 64?

34 mitotic divisions are needed for a single cell to make 1024 cells.

How many Equational divisions are necessary in a cell of onion root tip to form 64 cells?

Since this type of division results in two daughter cells from single parent cell. So, the formula is 2n, here n represents number of divisions. Thus the answer to the question can be calculated as: 2n= 264= 128.

How many mitotic divisions produce 64 cells?

A total of 6 rounds of mitotic division will form 64 daughter cells.