How many mitotic divisions in a root tip will form 256 cells?
(2)^n =256 (2)^8(2 raise to 8)=256 So number of mitotic division =8 after mitosis 2 daughter cells are formed.
How many mitotic divisions occur in a cell of root tip to form 256 cells a 128 B 8 C 10 D 255?
1→22→43→84→165→5 ↓5 326→647→128↓2256 It can be done with a simple formula (2)n, where n is the number of mitotic, division (2)n=256 (2)8=256(2×2×2×2×2×2×2×2=256) So, 8 mitotic division.
How many meiotic divisions are required to produce 256 cells in a root tip?
It takes 8 mitotic division to produce 256 cells in a root tip cell. Explanation: Cell division is of two types. They are mitosis and meiosis.
How many mitotic generations are required to produce 256 cells?
So we can conclude that eight mitotic divisions are required to produce $256$ daughters/somatic cells.
How many mitotic divisions occur in a cell of root tip to form 128 cells?
The cell will have to divide 7 times mitotically, to form 128 cells. The number of times a cell will have to divide mitotically is calculated by the formula 2n, where n is the number of times the cell is dividing.
How many mitotic divisions must occur in a cell to form 1024 cells A 20 B 10 C 40 D 64?
“34 mitotic divisions are needed for a single cell to make 1024 cells.
How many Equational divisions are necessary in a cell of onion root tip to form 64 cells?
Since this type of division results in two daughter cells from single parent cell. So, the formula is 2n, here n represents number of divisions. Thus the answer to the question can be calculated as: 2n= 264= 128.
How many mitotic divisions produce 64 cells?
A total of 6 rounds of mitotic division will form 64 daughter cells.