# How do you calculate the number of different types of gametes?

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## How do you determine the number of different genotypes?

The number of different genotypes is 3 n where n = number of genes. For simple dominant–recessive relations, the number of different phenotypes is 2 n , where n = number of genes.

## How many different gametes are in AaBbCc?

Hints For Biology 101 Exam #4

No. of homologous chromosome pairs (heterozygous genes) No. of different gametes from each parent
1 (Aa X Aa) 2 (21)
2 (AaBb X AaBb) 4 (22)
3 (AaBbCc X AaBbCc) 8 (23)
4 (AaBbCcDd X AaBbCcDd) 16 (24)

## How many unique gametes are produced?

The correct answer is (b) 8. In this scenario, each gamete will consist of five genes.

## How many different types of gametes can be formed by individuals of the genotype?

An individual with the genotype Aa can make two types of gametes: A and a. Since this is a random process, the individual will, on average, make equal numbers of each gamete. (Frequency of 1/2 for each gamete). A second individual with genotype Aa can make two types of gametes: A and a.

## What is the number of phenotypes possible from AaBbCc AaBbCc?

There is a formula to know the number of possible phenotypes from two parents which is \${2^n}\$ in which n describes the number of pairs of characters. In the above cross\$AaBbCc times AaBbCc\$, there are three pairs of characters which are Aa, Bb, Cc. Therefore, the number of possible phenotypes are \${2^3} = 8\$.

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