How do you calculate the number of different types of gametes?

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How do you determine the number of different genotypes?

The number of different genotypes is 3 n where n = number of genes. For simple dominant–recessive relations, the number of different phenotypes is 2 n , where n = number of genes.

How many different gametes are in AaBbCc?

Hints For Biology 101 Exam #4

No. of homologous chromosome pairs (heterozygous genes) No. of different gametes from each parent
1 (Aa X Aa) 2 (21)
2 (AaBb X AaBb) 4 (22)
3 (AaBbCc X AaBbCc) 8 (23)
4 (AaBbCcDd X AaBbCcDd) 16 (24)

How many unique gametes are produced?

The correct answer is (b) 8. In this scenario, each gamete will consist of five genes.

How many different types of gametes can be formed by individuals of the genotype?

An individual with the genotype Aa can make two types of gametes: A and a. Since this is a random process, the individual will, on average, make equal numbers of each gamete. (Frequency of 1/2 for each gamete). A second individual with genotype Aa can make two types of gametes: A and a.

What is the number of phenotypes possible from AaBbCc AaBbCc?

There is a formula to know the number of possible phenotypes from two parents which is ${2^n}$ in which n describes the number of pairs of characters. In the above cross$AaBbCc times AaBbCc$, there are three pairs of characters which are Aa, Bb, Cc. Therefore, the number of possible phenotypes are ${2^3} = 8$.

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